0,2x-5x^2=0

Solution for 0,2x-5x^2=0 equation:

0.2x-5x^2=0

a = -5; b = 0.2; c = 0;
Δ = b2-4ac
Δ = 0.22-4·(-5)·0
Δ = 0.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.2)-\sqrt{0.04}}{2*-5}=\frac{-0.2-\sqrt{0.04}}{-10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.2)+\sqrt{0.04}}{2*-5}=\frac{-0.2+\sqrt{0.04}}{-10}
$